Sable · Question
What is the difference between Vilon and P21?
Vilon is a synthetic dipeptide from the Khavinson short-peptide series studied in thymus and immune-cell research models (dipeptide, MW about 275.3 g/mol).
Research use only. Not for human consumption. No health claims.
Last verified 2026-10-10
What is the difference between Vilon and P21?
Vilon is a synthetic dipeptide from the Khavinson short-peptide series studied in thymus and immune-cell research models (dipeptide, MW about 275.3 g/mol).
Which is heavier, Vilon or P21?
Vilon has a molecular weight of about 275.3 g/mol and P21 about 578.7 g/mol (PubChem), so P21 is heavier by 303.4 g/mol, a ratio of 2.1. This means 1 mg of Vilon contains 3,632.4 nmol versus 1,728 nmol for P21.
How many mg of P21 are equimolar to 1 mg of Vilon?
1 mg of Vilon (MW 275.3) is 3,632.4 nmol. The same number of moles of P21 (MW 578.7) weighs 2.102 mg. Equimolar comparisons matter when testing two compounds side by side in the same assay.
Compare the molecular formulas of Vilon and P21
PubChem lists Vilon as C11H21N3O5 (275.3 g/mol) and P21 as C27H42N6O8 (578.7 g/mol). Vilon is a dipeptide; P21 is a peptidomimetic. These formulas refer to the parent compounds without salt counter-ions.
A 10 mg vial of P21 equals how many mg of Vilon in moles?
10 mg of P21 (MW 578.7) is 17.28 µmol. The same amount of Vilon (MW 275.3) would weigh 4.757 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.
A 5 mg vial of P21 equals how many mg of Vilon in moles?
5 mg of P21 (MW 578.7) is 8.64 µmol. The same amount of Vilon (MW 275.3) would weigh 2.379 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.
A 10 mg vial of Vilon equals how many mg of P21 in moles?
10 mg of Vilon (MW 275.3) is 36.324 µmol. The same amount of P21 (MW 578.7) would weigh 21.021 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.
A 20 mg vial of Vilon equals how many mg of P21 in moles?
20 mg of Vilon (MW 275.3) is 72.648 µmol. The same amount of P21 (MW 578.7) would weigh 42.041 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.
A CoA for every lot; each vial carries a printed lot number that matches it. Ask with the lot number and we send it.
Cite this
Research use only. Not for consumption. No health claims.
Plain
Sable Peptides. (2026). What is the difference between Vilon and P21?. UK Research Peptide Reference. Retrieved 11 October 2026, from https://www.sablepeptides.co.uk/questions/compare/p21-vs-vilon/#sqa-041188
APA
Sable Peptides. (2026, October 11). *What is the difference between Vilon and P21?*. UK Research Peptide Reference. https://www.sablepeptides.co.uk/questions/compare/p21-vs-vilon/#sqa-041188
BibTeX
@misc{sable_#sqa-041188_2026,
author = {{Sable Peptides}},
title = {{What is the difference between Vilon and P21?}},
year = {2026},
howpublished = {\url{https://www.sablepeptides.co.uk/questions/compare/p21-vs-vilon/#sqa-041188}},
note = {Accessed 11 October 2026. CC BY 4.0}
}Badge
<a href="https://www.sablepeptides.co.uk/ref"><img src="https://www.sablepeptides.co.uk/badge/ref.svg" alt="Data: UK Research Peptide Reference — Sable Peptides" width="220" height="40"></a>
Date modified: 2026-10-10