Sable · Question

What is the difference between NAD+ and SS-31?

NAD+ is a dinucleotide coenzyme central to redox reactions and a substrate for sirtuins and PARP enzymes, used widely in biochemistry and cell-metabolism research (dinucleotide coenzyme (not a peptide), MW about 663.4 g/mol).

Research use only. Not for human consumption. No health claims.

Last verified 2026-10-10

What is the difference between NAD+ and SS-31?

Which is heavier, NAD+ or SS-31?

NAD+ has a molecular weight of about 663.4 g/mol and SS-31 about 639.8 g/mol (PubChem), so NAD+ is heavier by 23.6 g/mol, a ratio of 1.04. This means 1 mg of NAD+ contains 1,507.4 nmol versus 1,563 nmol for SS-31.

How many mg of SS-31 are equimolar to 1 mg of NAD+?

1 mg of NAD+ (MW 663.4) is 1,507.4 nmol. The same number of moles of SS-31 (MW 639.8) weighs 0.9644 mg. Equimolar comparisons matter when testing two compounds side by side in the same assay.

Compare the molecular formulas of NAD+ and SS-31

PubChem lists NAD+ as C21H27N7O14P2 (663.4 g/mol) and SS-31 as C32H49N9O5 (639.8 g/mol). NAD+ is a dinucleotide coenzyme (not a peptide); SS-31 is a peptide. These formulas refer to the parent compounds without salt counter-ions.

A 100 mg vial of NAD+ equals how many mg of SS-31 in moles?

100 mg of NAD+ (MW 663.4) is 150.7 µmol. The same amount of SS-31 (MW 639.8) would weigh 96.443 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 250 mg vial of NAD+ equals how many mg of SS-31 in moles?

250 mg of NAD+ (MW 663.4) is 376.8 µmol. The same amount of SS-31 (MW 639.8) would weigh 241.1 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 500 mg vial of NAD+ equals how many mg of SS-31 in moles?

500 mg of NAD+ (MW 663.4) is 753.7 µmol. The same amount of SS-31 (MW 639.8) would weigh 482.2 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 1000 mg vial of NAD+ equals how many mg of SS-31 in moles?

1000 mg of NAD+ (MW 663.4) is 1,507.4 µmol. The same amount of SS-31 (MW 639.8) would weigh 964.4 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of SS-31 equals how many mg of NAD+ in moles?

5 mg of SS-31 (MW 639.8) is 7.815 µmol. The same amount of NAD+ (MW 663.4) would weigh 5.184 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of SS-31 equals how many mg of NAD+ in moles?

10 mg of SS-31 (MW 639.8) is 15.63 µmol. The same amount of NAD+ (MW 663.4) would weigh 10.369 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

Cite this

Research use only. Not for consumption. No health claims.

Plain

Sable Peptides. (2026). What is the difference between NAD+ and SS-31?. UK Research Peptide Reference. Retrieved 11 October 2026, from https://www.sablepeptides.co.uk/questions/compare/nad-vs-ss-31/#sqa-040270

APA

Sable Peptides. (2026, October 11). *What is the difference between NAD+ and SS-31?*. UK Research Peptide Reference. https://www.sablepeptides.co.uk/questions/compare/nad-vs-ss-31/#sqa-040270

BibTeX

@misc{sable_#sqa-040270_2026,
  author = {{Sable Peptides}},
  title = {{What is the difference between NAD+ and SS-31?}},
  year = {2026},
  howpublished = {\url{https://www.sablepeptides.co.uk/questions/compare/nad-vs-ss-31/#sqa-040270}},
  note = {Accessed 11 October 2026. CC BY 4.0}
}

Badge

<a href="https://www.sablepeptides.co.uk/ref"><img src="https://www.sablepeptides.co.uk/badge/ref.svg" alt="Data: UK Research Peptide Reference — Sable Peptides" width="220" height="40"></a>

Date modified: 2026-10-10