Sable · Question

What is the difference between NAD+ and PT-141?

NAD+ is a dinucleotide coenzyme central to redox reactions and a substrate for sirtuins and PARP enzymes, used widely in biochemistry and cell-metabolism research (dinucleotide coenzyme (not a peptide), MW about 663.4 g/mol).

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Last verified 2026-10-10

What is the difference between NAD+ and PT-141?

Which is heavier, NAD+ or PT-141?

NAD+ has a molecular weight of about 663.4 g/mol and PT-141 about 1025.2 g/mol (PubChem), so PT-141 is heavier by 361.8 g/mol, a ratio of 1.55. This means 1 mg of NAD+ contains 1,507.4 nmol versus 975.4 nmol for PT-141.

How many mg of PT-141 are equimolar to 1 mg of NAD+?

1 mg of NAD+ (MW 663.4) is 1,507.4 nmol. The same number of moles of PT-141 (MW 1025.2) weighs 1.545 mg. Equimolar comparisons matter when testing two compounds side by side in the same assay.

Compare the molecular formulas of NAD+ and PT-141

PubChem lists NAD+ as C21H27N7O14P2 (663.4 g/mol) and PT-141 as C50H68N14O10 (1025.2 g/mol). NAD+ is a dinucleotide coenzyme (not a peptide); PT-141 is a cyclic peptide. These formulas refer to the parent compounds without salt counter-ions.

A 100 mg vial of NAD+ equals how many mg of PT-141 in moles?

100 mg of NAD+ (MW 663.4) is 150.7 µmol. The same amount of PT-141 (MW 1025.2) would weigh 154.5 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 250 mg vial of NAD+ equals how many mg of PT-141 in moles?

250 mg of NAD+ (MW 663.4) is 376.8 µmol. The same amount of PT-141 (MW 1025.2) would weigh 386.3 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 500 mg vial of NAD+ equals how many mg of PT-141 in moles?

500 mg of NAD+ (MW 663.4) is 753.7 µmol. The same amount of PT-141 (MW 1025.2) would weigh 772.7 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 1000 mg vial of NAD+ equals how many mg of PT-141 in moles?

1000 mg of NAD+ (MW 663.4) is 1,507.4 µmol. The same amount of PT-141 (MW 1025.2) would weigh 1,545.4 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of PT-141 equals how many mg of NAD+ in moles?

10 mg of PT-141 (MW 1025.2) is 9.754 µmol. The same amount of NAD+ (MW 663.4) would weigh 6.471 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of PT-141 equals how many mg of NAD+ in moles?

5 mg of PT-141 (MW 1025.2) is 4.877 µmol. The same amount of NAD+ (MW 663.4) would weigh 3.235 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

Cite this

Research use only. Not for consumption. No health claims.

Plain

Sable Peptides. (2026). What is the difference between NAD+ and PT-141?. UK Research Peptide Reference. Retrieved 11 October 2026, from https://www.sablepeptides.co.uk/questions/compare/nad-vs-pt-141/#sqa-040262

APA

Sable Peptides. (2026, October 11). *What is the difference between NAD+ and PT-141?*. UK Research Peptide Reference. https://www.sablepeptides.co.uk/questions/compare/nad-vs-pt-141/#sqa-040262

BibTeX

@misc{sable_#sqa-040262_2026,
  author = {{Sable Peptides}},
  title = {{What is the difference between NAD+ and PT-141?}},
  year = {2026},
  howpublished = {\url{https://www.sablepeptides.co.uk/questions/compare/nad-vs-pt-141/#sqa-040262}},
  note = {Accessed 11 October 2026. CC BY 4.0}
}

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Date modified: 2026-10-10