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What is the difference between NAD+ and P21?

NAD+ is a dinucleotide coenzyme central to redox reactions and a substrate for sirtuins and PARP enzymes, used widely in biochemistry and cell-metabolism research (dinucleotide coenzyme (not a peptide), MW about 663.4 g/mol).

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Last verified 2026-10-10

What is the difference between NAD+ and P21?

NAD+ is a dinucleotide coenzyme central to redox reactions and a substrate for sirtuins and PARP enzymes, used widely in biochemistry and cell-metabolism research (dinucleotide coenzyme (not a peptide), MW about 663.4 g/mol).

Which is heavier, NAD+ or P21?

NAD+ has a molecular weight of about 663.4 g/mol and P21 about 578.7 g/mol (PubChem), so NAD+ is heavier by 84.7 g/mol, a ratio of 1.15. This means 1 mg of NAD+ contains 1,507.4 nmol versus 1,728 nmol for P21.

How many mg of P21 are equimolar to 1 mg of NAD+?

1 mg of NAD+ (MW 663.4) is 1,507.4 nmol. The same number of moles of P21 (MW 578.7) weighs 0.8723 mg. Equimolar comparisons matter when testing two compounds side by side in the same assay.

Compare the molecular formulas of NAD+ and P21

PubChem lists NAD+ as C21H27N7O14P2 (663.4 g/mol) and P21 as C27H42N6O8 (578.7 g/mol). NAD+ is a dinucleotide coenzyme (not a peptide); P21 is a peptidomimetic. These formulas refer to the parent compounds without salt counter-ions.

A 100 mg vial of NAD+ equals how many mg of P21 in moles?

100 mg of NAD+ (MW 663.4) is 150.7 µmol. The same amount of P21 (MW 578.7) would weigh 87.232 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 250 mg vial of NAD+ equals how many mg of P21 in moles?

250 mg of NAD+ (MW 663.4) is 376.8 µmol. The same amount of P21 (MW 578.7) would weigh 218.1 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 500 mg vial of NAD+ equals how many mg of P21 in moles?

500 mg of NAD+ (MW 663.4) is 753.7 µmol. The same amount of P21 (MW 578.7) would weigh 436.2 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 1000 mg vial of NAD+ equals how many mg of P21 in moles?

1000 mg of NAD+ (MW 663.4) is 1,507.4 µmol. The same amount of P21 (MW 578.7) would weigh 872.3 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of P21 equals how many mg of NAD+ in moles?

10 mg of P21 (MW 578.7) is 17.28 µmol. The same amount of NAD+ (MW 663.4) would weigh 11.464 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of P21 equals how many mg of NAD+ in moles?

5 mg of P21 (MW 578.7) is 8.64 µmol. The same amount of NAD+ (MW 663.4) would weigh 5.732 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

More questions about nad

A CoA for every lot; each vial carries a printed lot number that matches it. Ask with the lot number and we send it.

Cite this

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Plain

Sable Peptides. (2026). What is the difference between NAD+ and P21?. UK Research Peptide Reference. Retrieved 11 October 2026, from https://www.sablepeptides.co.uk/questions/compare/nad-vs-p21/#sqa-040334

APA

Sable Peptides. (2026, October 11). *What is the difference between NAD+ and P21?*. UK Research Peptide Reference. https://www.sablepeptides.co.uk/questions/compare/nad-vs-p21/#sqa-040334

BibTeX

@misc{sable_#sqa-040334_2026,
  author = {{Sable Peptides}},
  title = {{What is the difference between NAD+ and P21?}},
  year = {2026},
  howpublished = {\url{https://www.sablepeptides.co.uk/questions/compare/nad-vs-p21/#sqa-040334}},
  note = {Accessed 11 October 2026. CC BY 4.0}
}

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Date modified: 2026-10-10