Sable · Question

A 5 mg vial of SS-31 equals how many mg of Melanotan II in moles?

5 mg of SS-31 (MW 639.8) is 7.815 µmol. The same amount of Melanotan II (MW 1024.2) would weigh 8.004 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

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Last verified 2026-10-10

A 5 mg vial of SS-31 equals how many mg of Melanotan II in moles?

A 10 mg vial of SS-31 equals how many mg of Melanotan II in moles?

10 mg of SS-31 (MW 639.8) is 15.63 µmol. The same amount of Melanotan II (MW 1024.2) would weigh 16.008 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

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Research use only. Not for consumption. No health claims.

Plain

Sable Peptides. (2026). A 5 mg vial of SS-31 equals how many mg of Melanotan II in moles?. UK Research Peptide Reference. Retrieved 11 October 2026, from https://www.sablepeptides.co.uk/questions/compare/melanotan-ii-vs-ss-31/#sqa-045320

APA

Sable Peptides. (2026, October 11). *A 5 mg vial of SS-31 equals how many mg of Melanotan II in moles?*. UK Research Peptide Reference. https://www.sablepeptides.co.uk/questions/compare/melanotan-ii-vs-ss-31/#sqa-045320

BibTeX

@misc{sable_#sqa-045320_2026,
  author = {{Sable Peptides}},
  title = {{A 5 mg vial of SS-31 equals how many mg of Melanotan II in moles?}},
  year = {2026},
  howpublished = {\url{https://www.sablepeptides.co.uk/questions/compare/melanotan-ii-vs-ss-31/#sqa-045320}},
  note = {Accessed 11 October 2026. CC BY 4.0}
}

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Date modified: 2026-10-10