Sable · Question
What is the difference between MOTS-c and Melanotan II?
MOTS-c is a 16-residue mitochondrial-derived peptide encoded in the 12S rRNA region, described in 2015 and studied in cellular metabolism research (peptide, MW about 2174.6 g/mol).
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Last verified 2026-10-10
What is the difference between MOTS-c and Melanotan II?
MOTS-c is a 16-residue mitochondrial-derived peptide encoded in the 12S rRNA region, described in 2015 and studied in cellular metabolism research (peptide, MW about 2174.6 g/mol).
Which is heavier, MOTS-c or Melanotan II?
MOTS-c has a molecular weight of about 2174.6 g/mol and Melanotan II about 1024.2 g/mol (PubChem), so MOTS-c is heavier by 1,150.4 g/mol, a ratio of 2.12. This means 1 mg of MOTS-c contains 459.9 nmol versus 976.4 nmol for Melanotan II.
How many mg of Melanotan II are equimolar to 1 mg of MOTS-c?
1 mg of MOTS-c (MW 2174.6) is 459.9 nmol. The same number of moles of Melanotan II (MW 1024.2) weighs 0.471 mg. Equimolar comparisons matter when testing two compounds side by side in the same assay.
Compare the molecular formulas of MOTS-c and Melanotan II
PubChem lists MOTS-c as C101H152N28O22S2 (2174.6 g/mol) and Melanotan II as C50H69N15O9 (1024.2 g/mol). MOTS-c is a peptide; Melanotan II is a cyclic peptide. These formulas refer to the parent compounds without salt counter-ions.
A 5 mg vial of MOTS-c equals how many mg of Melanotan II in moles?
5 mg of MOTS-c (MW 2174.6) is 2.299 µmol. The same amount of Melanotan II (MW 1024.2) would weigh 2.355 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.
A 10 mg vial of MOTS-c equals how many mg of Melanotan II in moles?
10 mg of MOTS-c (MW 2174.6) is 4.599 µmol. The same amount of Melanotan II (MW 1024.2) would weigh 4.71 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.
A 20 mg vial of MOTS-c equals how many mg of Melanotan II in moles?
20 mg of MOTS-c (MW 2174.6) is 9.197 µmol. The same amount of Melanotan II (MW 1024.2) would weigh 9.42 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.
A 30 mg vial of MOTS-c equals how many mg of Melanotan II in moles?
30 mg of MOTS-c (MW 2174.6) is 13.796 µmol. The same amount of Melanotan II (MW 1024.2) would weigh 14.129 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.
A 40 mg vial of MOTS-c equals how many mg of Melanotan II in moles?
40 mg of MOTS-c (MW 2174.6) is 18.394 µmol. The same amount of Melanotan II (MW 1024.2) would weigh 18.839 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.
A CoA for every lot; each vial carries a printed lot number that matches it. Ask with the lot number and we send it.
Cite this
Research use only. Not for consumption. No health claims.
Plain
Sable Peptides. (2026). What is the difference between MOTS-c and Melanotan II?. UK Research Peptide Reference. Retrieved 11 October 2026, from https://www.sablepeptides.co.uk/questions/compare/melanotan-ii-vs-mots-c/#sqa-039965
APA
Sable Peptides. (2026, October 11). *What is the difference between MOTS-c and Melanotan II?*. UK Research Peptide Reference. https://www.sablepeptides.co.uk/questions/compare/melanotan-ii-vs-mots-c/#sqa-039965
BibTeX
@misc{sable_#sqa-039965_2026,
author = {{Sable Peptides}},
title = {{What is the difference between MOTS-c and Melanotan II?}},
year = {2026},
howpublished = {\url{https://www.sablepeptides.co.uk/questions/compare/melanotan-ii-vs-mots-c/#sqa-039965}},
note = {Accessed 11 October 2026. CC BY 4.0}
}Badge
<a href="https://www.sablepeptides.co.uk/ref"><img src="https://www.sablepeptides.co.uk/badge/ref.svg" alt="Data: UK Research Peptide Reference — Sable Peptides" width="220" height="40"></a>
Date modified: 2026-10-10