Sable · Question

What is the difference between Melanotan I and NAD+?

Melanotan I is a linear 13-residue alpha-MSH analogue used in melanocortin-1 receptor research (peptide, MW about 1646.8 g/mol).

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Last verified 2026-10-10

What is the difference between Melanotan I and NAD+?

Melanotan I is a linear 13-residue alpha-MSH analogue used in melanocortin-1 receptor research (peptide, MW about 1646.8 g/mol).

Which is heavier, Melanotan I or NAD+?

Melanotan I has a molecular weight of about 1646.8 g/mol and NAD+ about 663.4 g/mol (PubChem), so Melanotan I is heavier by 983.4 g/mol, a ratio of 2.48. This means 1 mg of Melanotan I contains 607.2 nmol versus 1,507.4 nmol for NAD+.

How many mg of NAD+ are equimolar to 1 mg of Melanotan I?

1 mg of Melanotan I (MW 1646.8) is 607.2 nmol. The same number of moles of NAD+ (MW 663.4) weighs 0.4028 mg. Equimolar comparisons matter when testing two compounds side by side in the same assay.

Compare the molecular formulas of Melanotan I and NAD+

PubChem lists Melanotan I as C78H111N21O19 (1646.8 g/mol) and NAD+ as C21H27N7O14P2 (663.4 g/mol). Melanotan I is a peptide; NAD+ is a dinucleotide coenzyme (not a peptide). These formulas refer to the parent compounds without salt counter-ions.

A 5 mg vial of Melanotan I equals how many mg of NAD+ in moles?

5 mg of Melanotan I (MW 1646.8) is 3.036 µmol. The same amount of NAD+ (MW 663.4) would weigh 2.014 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan I equals how many mg of NAD+ in moles?

10 mg of Melanotan I (MW 1646.8) is 6.072 µmol. The same amount of NAD+ (MW 663.4) would weigh 4.028 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 100 mg vial of NAD+ equals how many mg of Melanotan I in moles?

100 mg of NAD+ (MW 663.4) is 150.7 µmol. The same amount of Melanotan I (MW 1646.8) would weigh 248.2 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 250 mg vial of NAD+ equals how many mg of Melanotan I in moles?

250 mg of NAD+ (MW 663.4) is 376.8 µmol. The same amount of Melanotan I (MW 1646.8) would weigh 620.6 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 500 mg vial of NAD+ equals how many mg of Melanotan I in moles?

500 mg of NAD+ (MW 663.4) is 753.7 µmol. The same amount of Melanotan I (MW 1646.8) would weigh 1,241.2 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 1000 mg vial of NAD+ equals how many mg of Melanotan I in moles?

1000 mg of NAD+ (MW 663.4) is 1,507.4 µmol. The same amount of Melanotan I (MW 1646.8) would weigh 2,482.4 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

Cite this

Research use only. Not for consumption. No health claims.

Plain

Sable Peptides. (2026). What is the difference between Melanotan I and NAD+?. UK Research Peptide Reference. Retrieved 11 October 2026, from https://www.sablepeptides.co.uk/questions/compare/melanotan-i-vs-nad/#sqa-040068

APA

Sable Peptides. (2026, October 11). *What is the difference between Melanotan I and NAD+?*. UK Research Peptide Reference. https://www.sablepeptides.co.uk/questions/compare/melanotan-i-vs-nad/#sqa-040068

BibTeX

@misc{sable_#sqa-040068_2026,
  author = {{Sable Peptides}},
  title = {{What is the difference between Melanotan I and NAD+?}},
  year = {2026},
  howpublished = {\url{https://www.sablepeptides.co.uk/questions/compare/melanotan-i-vs-nad/#sqa-040068}},
  note = {Accessed 11 October 2026. CC BY 4.0}
}

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Date modified: 2026-10-10