Sable · Question

What is the difference between Melanotan I and Melanotan II?

Melanotan I is a linear 13-residue alpha-MSH analogue used in melanocortin-1 receptor research (peptide, MW about 1646.8 g/mol).

Research use only. Not for human consumption. No health claims.

Last verified 2026-10-10

What is the difference between Melanotan I and Melanotan II?

Melanotan I is a linear 13-residue alpha-MSH analogue used in melanocortin-1 receptor research (peptide, MW about 1646.8 g/mol).

Which is heavier, Melanotan I or Melanotan II?

Melanotan I has a molecular weight of about 1646.8 g/mol and Melanotan II about 1024.2 g/mol (PubChem), so Melanotan I is heavier by 622.6 g/mol, a ratio of 1.61. This means 1 mg of Melanotan I contains 607.2 nmol versus 976.4 nmol for Melanotan II.

How many mg of Melanotan II are equimolar to 1 mg of Melanotan I?

1 mg of Melanotan I (MW 1646.8) is 607.2 nmol. The same number of moles of Melanotan II (MW 1024.2) weighs 0.6219 mg. Equimolar comparisons matter when testing two compounds side by side in the same assay.

Compare the molecular formulas of Melanotan I and Melanotan II

PubChem lists Melanotan I as C78H111N21O19 (1646.8 g/mol) and Melanotan II as C50H69N15O9 (1024.2 g/mol). Melanotan I is a peptide; Melanotan II is a cyclic peptide. These formulas refer to the parent compounds without salt counter-ions.

What is the difference between Melanotan II and NAD+?

Melanotan II is a cyclic heptapeptide alpha-MSH analogue used as a non-selective melanocortin receptor agonist in receptor-pharmacology research (cyclic peptide, MW about 1024.2 g/mol).

Which is heavier, Melanotan II or NAD+?

Melanotan II has a molecular weight of about 1024.2 g/mol and NAD+ about 663.4 g/mol (PubChem), so Melanotan II is heavier by 360.8 g/mol, a ratio of 1.54. This means 1 mg of Melanotan II contains 976.4 nmol versus 1,507.4 nmol for NAD+.

How many mg of NAD+ are equimolar to 1 mg of Melanotan II?

1 mg of Melanotan II (MW 1024.2) is 976.4 nmol. The same number of moles of NAD+ (MW 663.4) weighs 0.6477 mg. Equimolar comparisons matter when testing two compounds side by side in the same assay.

Compare the molecular formulas of Melanotan II and NAD+

PubChem lists Melanotan II as C50H69N15O9 (1024.2 g/mol) and NAD+ as C21H27N7O14P2 (663.4 g/mol). Melanotan II is a cyclic peptide; NAD+ is a dinucleotide coenzyme (not a peptide). These formulas refer to the parent compounds without salt counter-ions.

What is the difference between Melanotan II and Oxytocin?

Melanotan II is a cyclic heptapeptide alpha-MSH analogue used as a non-selective melanocortin receptor agonist in receptor-pharmacology research (cyclic peptide, MW about 1024.2 g/mol).

Which is heavier, Melanotan II or Oxytocin?

Melanotan II has a molecular weight of about 1024.2 g/mol and Oxytocin about 1007.2 g/mol (PubChem), so Melanotan II is heavier by 17 g/mol, a ratio of 1.02. This means 1 mg of Melanotan II contains 976.4 nmol versus 992.9 nmol for Oxytocin.

How many mg of Oxytocin are equimolar to 1 mg of Melanotan II?

1 mg of Melanotan II (MW 1024.2) is 976.4 nmol. The same number of moles of Oxytocin (MW 1007.2) weighs 0.9834 mg. Equimolar comparisons matter when testing two compounds side by side in the same assay.

Compare the molecular formulas of Melanotan II and Oxytocin

PubChem lists Melanotan II as C50H69N15O9 (1024.2 g/mol) and Oxytocin as C43H66N12O12S2 (1007.2 g/mol). Melanotan II is a cyclic peptide; Oxytocin is a cyclic nonapeptide. These formulas refer to the parent compounds without salt counter-ions.

What is the difference between Melanotan II and PT-141?

Melanotan II is a cyclic heptapeptide alpha-MSH analogue used as a non-selective melanocortin receptor agonist in receptor-pharmacology research (cyclic peptide, MW about 1024.2 g/mol).

Which is heavier, Melanotan II or PT-141?

Melanotan II has a molecular weight of about 1024.2 g/mol and PT-141 about 1025.2 g/mol (PubChem), so PT-141 is heavier by 1 g/mol, a ratio of 1. This means 1 mg of Melanotan II contains 976.4 nmol versus 975.4 nmol for PT-141.

How many mg of PT-141 are equimolar to 1 mg of Melanotan II?

1 mg of Melanotan II (MW 1024.2) is 976.4 nmol. The same number of moles of PT-141 (MW 1025.2) weighs 1.001 mg. Equimolar comparisons matter when testing two compounds side by side in the same assay.

Compare the molecular formulas of Melanotan II and PT-141

PubChem lists Melanotan II as C50H69N15O9 (1024.2 g/mol) and PT-141 as C50H68N14O10 (1025.2 g/mol). Melanotan II is a cyclic peptide; PT-141 is a cyclic peptide. These formulas refer to the parent compounds without salt counter-ions.

What is the difference between Melanotan II and SLU-PP-332?

Melanotan II is a cyclic heptapeptide alpha-MSH analogue used as a non-selective melanocortin receptor agonist in receptor-pharmacology research (cyclic peptide, MW about 1024.2 g/mol).

Which is heavier, Melanotan II or SLU-PP-332?

Melanotan II has a molecular weight of about 1024.2 g/mol and SLU-PP-332 about 290.3 g/mol (PubChem), so Melanotan II is heavier by 733.9 g/mol, a ratio of 3.53. This means 1 mg of Melanotan II contains 976.4 nmol versus 3,444.7 nmol for SLU-PP-332.

How many mg of SLU-PP-332 are equimolar to 1 mg of Melanotan II?

1 mg of Melanotan II (MW 1024.2) is 976.4 nmol. The same number of moles of SLU-PP-332 (MW 290.3) weighs 0.2834 mg. Equimolar comparisons matter when testing two compounds side by side in the same assay.

Compare the molecular formulas of Melanotan II and SLU-PP-332

PubChem lists Melanotan II as C50H69N15O9 (1024.2 g/mol) and SLU-PP-332 as C18H14N2O2 (290.3 g/mol). Melanotan II is a cyclic peptide; SLU-PP-332 is a small molecule (not a peptide). These formulas refer to the parent compounds without salt counter-ions.

What is the difference between Melanotan II and SS-31?

Melanotan II is a cyclic heptapeptide alpha-MSH analogue used as a non-selective melanocortin receptor agonist in receptor-pharmacology research (cyclic peptide, MW about 1024.2 g/mol).

Which is heavier, Melanotan II or SS-31?

Melanotan II has a molecular weight of about 1024.2 g/mol and SS-31 about 639.8 g/mol (PubChem), so Melanotan II is heavier by 384.4 g/mol, a ratio of 1.6. This means 1 mg of Melanotan II contains 976.4 nmol versus 1,563 nmol for SS-31.

How many mg of SS-31 are equimolar to 1 mg of Melanotan II?

1 mg of Melanotan II (MW 1024.2) is 976.4 nmol. The same number of moles of SS-31 (MW 639.8) weighs 0.6247 mg. Equimolar comparisons matter when testing two compounds side by side in the same assay.

Compare the molecular formulas of Melanotan II and SS-31

PubChem lists Melanotan II as C50H69N15O9 (1024.2 g/mol) and SS-31 as C32H49N9O5 (639.8 g/mol). Melanotan II is a cyclic peptide; SS-31 is a peptide. These formulas refer to the parent compounds without salt counter-ions.

What is the difference between Melanotan II and Selank?

Melanotan II is a cyclic heptapeptide alpha-MSH analogue used as a non-selective melanocortin receptor agonist in receptor-pharmacology research (cyclic peptide, MW about 1024.2 g/mol).

Which is heavier, Melanotan II or Selank?

Melanotan II has a molecular weight of about 1024.2 g/mol and Selank about 751.9 g/mol (PubChem), so Melanotan II is heavier by 272.3 g/mol, a ratio of 1.36. This means 1 mg of Melanotan II contains 976.4 nmol versus 1,330 nmol for Selank.

How many mg of Selank are equimolar to 1 mg of Melanotan II?

1 mg of Melanotan II (MW 1024.2) is 976.4 nmol. The same number of moles of Selank (MW 751.9) weighs 0.7341 mg. Equimolar comparisons matter when testing two compounds side by side in the same assay.

Compare the molecular formulas of Melanotan II and Selank

PubChem lists Melanotan II as C50H69N15O9 (1024.2 g/mol) and Selank as C33H57N11O9 (751.9 g/mol). Melanotan II is a cyclic peptide; Selank is a peptide. These formulas refer to the parent compounds without salt counter-ions.

What is the difference between Melanotan II and Semaglutide?

Melanotan II is a cyclic heptapeptide alpha-MSH analogue used as a non-selective melanocortin receptor agonist in receptor-pharmacology research (cyclic peptide, MW about 1024.2 g/mol).

Which is heavier, Melanotan II or Semaglutide?

Melanotan II has a molecular weight of about 1024.2 g/mol and Semaglutide about 4114 g/mol (PubChem), so Semaglutide is heavier by 3,089.8 g/mol, a ratio of 4.02. This means 1 mg of Melanotan II contains 976.4 nmol versus 243.1 nmol for Semaglutide.

How many mg of Semaglutide are equimolar to 1 mg of Melanotan II?

1 mg of Melanotan II (MW 1024.2) is 976.4 nmol. The same number of moles of Semaglutide (MW 4114) weighs 4.017 mg. Equimolar comparisons matter when testing two compounds side by side in the same assay.

Compare the molecular formulas of Melanotan II and Semaglutide

PubChem lists Melanotan II as C50H69N15O9 (1024.2 g/mol) and Semaglutide as C187H291N45O59 (4114 g/mol). Melanotan II is a cyclic peptide; Semaglutide is a peptide (lipidated). These formulas refer to the parent compounds without salt counter-ions.

What is the difference between Melanotan II and Semax?

Melanotan II is a cyclic heptapeptide alpha-MSH analogue used as a non-selective melanocortin receptor agonist in receptor-pharmacology research (cyclic peptide, MW about 1024.2 g/mol).

Which is heavier, Melanotan II or Semax?

Melanotan II has a molecular weight of about 1024.2 g/mol and Semax about 813.9 g/mol (PubChem), so Melanotan II is heavier by 210.3 g/mol, a ratio of 1.26. This means 1 mg of Melanotan II contains 976.4 nmol versus 1,228.7 nmol for Semax.

How many mg of Semax are equimolar to 1 mg of Melanotan II?

1 mg of Melanotan II (MW 1024.2) is 976.4 nmol. The same number of moles of Semax (MW 813.9) weighs 0.7947 mg. Equimolar comparisons matter when testing two compounds side by side in the same assay.

Compare the molecular formulas of Melanotan II and Semax

PubChem lists Melanotan II as C50H69N15O9 (1024.2 g/mol) and Semax as C37H51N9O10S (813.9 g/mol). Melanotan II is a cyclic peptide; Semax is a peptide. These formulas refer to the parent compounds without salt counter-ions.

What is the difference between Melanotan II and Sermorelin?

Melanotan II is a cyclic heptapeptide alpha-MSH analogue used as a non-selective melanocortin receptor agonist in receptor-pharmacology research (cyclic peptide, MW about 1024.2 g/mol).

Which is heavier, Melanotan II or Sermorelin?

Melanotan II has a molecular weight of about 1024.2 g/mol and Sermorelin about 3357.9 g/mol (PubChem), so Sermorelin is heavier by 2,333.7 g/mol, a ratio of 3.28. This means 1 mg of Melanotan II contains 976.4 nmol versus 297.8 nmol for Sermorelin.

How many mg of Sermorelin are equimolar to 1 mg of Melanotan II?

1 mg of Melanotan II (MW 1024.2) is 976.4 nmol. The same number of moles of Sermorelin (MW 3357.9) weighs 3.279 mg. Equimolar comparisons matter when testing two compounds side by side in the same assay.

Compare the molecular formulas of Melanotan II and Sermorelin

PubChem lists Melanotan II as C50H69N15O9 (1024.2 g/mol) and Sermorelin as C149H246N44O42S (3357.9 g/mol). Melanotan II is a cyclic peptide; Sermorelin is a peptide. These formulas refer to the parent compounds without salt counter-ions.

What is the difference between Melanotan II and Tesamorelin?

Melanotan II is a cyclic heptapeptide alpha-MSH analogue used as a non-selective melanocortin receptor agonist in receptor-pharmacology research (cyclic peptide, MW about 1024.2 g/mol).

Which is heavier, Melanotan II or Tesamorelin?

Melanotan II has a molecular weight of about 1024.2 g/mol and Tesamorelin about 5136 g/mol (PubChem), so Tesamorelin is heavier by 4,111.8 g/mol, a ratio of 5.01. This means 1 mg of Melanotan II contains 976.4 nmol versus 194.7 nmol for Tesamorelin.

How many mg of Tesamorelin are equimolar to 1 mg of Melanotan II?

1 mg of Melanotan II (MW 1024.2) is 976.4 nmol. The same number of moles of Tesamorelin (MW 5136) weighs 5.015 mg. Equimolar comparisons matter when testing two compounds side by side in the same assay.

Compare the molecular formulas of Melanotan II and Tesamorelin

PubChem lists Melanotan II as C50H69N15O9 (1024.2 g/mol) and Tesamorelin as C221H366N72O67S (5136 g/mol). Melanotan II is a cyclic peptide; Tesamorelin is a peptide. These formulas refer to the parent compounds without salt counter-ions.

What is the difference between Melanotan II and Tirzepatide?

Melanotan II is a cyclic heptapeptide alpha-MSH analogue used as a non-selective melanocortin receptor agonist in receptor-pharmacology research (cyclic peptide, MW about 1024.2 g/mol).

Which is heavier, Melanotan II or Tirzepatide?

Melanotan II has a molecular weight of about 1024.2 g/mol and Tirzepatide about 4813 g/mol (PubChem), so Tirzepatide is heavier by 3,788.8 g/mol, a ratio of 4.7. This means 1 mg of Melanotan II contains 976.4 nmol versus 207.8 nmol for Tirzepatide.

How many mg of Tirzepatide are equimolar to 1 mg of Melanotan II?

1 mg of Melanotan II (MW 1024.2) is 976.4 nmol. The same number of moles of Tirzepatide (MW 4813) weighs 4.699 mg. Equimolar comparisons matter when testing two compounds side by side in the same assay.

Compare the molecular formulas of Melanotan II and Tirzepatide

PubChem lists Melanotan II as C50H69N15O9 (1024.2 g/mol) and Tirzepatide as C225H348N48O68 (4813 g/mol). Melanotan II is a cyclic peptide; Tirzepatide is a peptide (lipidated). These formulas refer to the parent compounds without salt counter-ions.

What is the difference between Melanotan II and Triptorelin?

Melanotan II is a cyclic heptapeptide alpha-MSH analogue used as a non-selective melanocortin receptor agonist in receptor-pharmacology research (cyclic peptide, MW about 1024.2 g/mol).

Which is heavier, Melanotan II or Triptorelin?

Melanotan II has a molecular weight of about 1024.2 g/mol and Triptorelin about 1311.4 g/mol (PubChem), so Triptorelin is heavier by 287.2 g/mol, a ratio of 1.28. This means 1 mg of Melanotan II contains 976.4 nmol versus 762.5 nmol for Triptorelin.

How many mg of Triptorelin are equimolar to 1 mg of Melanotan II?

1 mg of Melanotan II (MW 1024.2) is 976.4 nmol. The same number of moles of Triptorelin (MW 1311.4) weighs 1.28 mg. Equimolar comparisons matter when testing two compounds side by side in the same assay.

Compare the molecular formulas of Melanotan II and Triptorelin

PubChem lists Melanotan II as C50H69N15O9 (1024.2 g/mol) and Triptorelin as C64H82N18O13 (1311.4 g/mol). Melanotan II is a cyclic peptide; Triptorelin is a peptide. These formulas refer to the parent compounds without salt counter-ions.

What is the difference between Melanotan II and Pinealon?

Melanotan II is a cyclic heptapeptide alpha-MSH analogue used as a non-selective melanocortin receptor agonist in receptor-pharmacology research (cyclic peptide, MW about 1024.2 g/mol).

Which is heavier, Melanotan II or Pinealon?

Melanotan II has a molecular weight of about 1024.2 g/mol and Pinealon about 418.4 g/mol (PubChem), so Melanotan II is heavier by 605.8 g/mol, a ratio of 2.45. This means 1 mg of Melanotan II contains 976.4 nmol versus 2,390.1 nmol for Pinealon.

How many mg of Pinealon are equimolar to 1 mg of Melanotan II?

1 mg of Melanotan II (MW 1024.2) is 976.4 nmol. The same number of moles of Pinealon (MW 418.4) weighs 0.4085 mg. Equimolar comparisons matter when testing two compounds side by side in the same assay.

Compare the molecular formulas of Melanotan II and Pinealon

PubChem lists Melanotan II as C50H69N15O9 (1024.2 g/mol) and Pinealon as C15H26N6O8 (418.4 g/mol). Melanotan II is a cyclic peptide; Pinealon is a peptide. These formulas refer to the parent compounds without salt counter-ions.

What is the difference between Melanotan II and Vilon?

Melanotan II is a cyclic heptapeptide alpha-MSH analogue used as a non-selective melanocortin receptor agonist in receptor-pharmacology research (cyclic peptide, MW about 1024.2 g/mol).

Which is heavier, Melanotan II or Vilon?

Melanotan II has a molecular weight of about 1024.2 g/mol and Vilon about 275.3 g/mol (PubChem), so Melanotan II is heavier by 748.9 g/mol, a ratio of 3.72. This means 1 mg of Melanotan II contains 976.4 nmol versus 3,632.4 nmol for Vilon.

How many mg of Vilon are equimolar to 1 mg of Melanotan II?

1 mg of Melanotan II (MW 1024.2) is 976.4 nmol. The same number of moles of Vilon (MW 275.3) weighs 0.2688 mg. Equimolar comparisons matter when testing two compounds side by side in the same assay.

Compare the molecular formulas of Melanotan II and Vilon

PubChem lists Melanotan II as C50H69N15O9 (1024.2 g/mol) and Vilon as C11H21N3O5 (275.3 g/mol). Melanotan II is a cyclic peptide; Vilon is a dipeptide. These formulas refer to the parent compounds without salt counter-ions.

What is the difference between Melanotan II and Vesugen?

Melanotan II is a cyclic heptapeptide alpha-MSH analogue used as a non-selective melanocortin receptor agonist in receptor-pharmacology research (cyclic peptide, MW about 1024.2 g/mol).

Which is heavier, Melanotan II or Vesugen?

Melanotan II has a molecular weight of about 1024.2 g/mol and Vesugen about 390.39 g/mol (PubChem), so Melanotan II is heavier by 633.8 g/mol, a ratio of 2.62. This means 1 mg of Melanotan II contains 976.4 nmol versus 2,561.5 nmol for Vesugen.

How many mg of Vesugen are equimolar to 1 mg of Melanotan II?

1 mg of Melanotan II (MW 1024.2) is 976.4 nmol. The same number of moles of Vesugen (MW 390.39) weighs 0.3812 mg. Equimolar comparisons matter when testing two compounds side by side in the same assay.

Compare the molecular formulas of Melanotan II and Vesugen

PubChem lists Melanotan II as C50H69N15O9 (1024.2 g/mol) and Vesugen as C15H26N4O8 (390.39 g/mol). Melanotan II is a cyclic peptide; Vesugen is a peptide. These formulas refer to the parent compounds without salt counter-ions.

What is the difference between Melanotan II and Cartalax?

Melanotan II is a cyclic heptapeptide alpha-MSH analogue used as a non-selective melanocortin receptor agonist in receptor-pharmacology research (cyclic peptide, MW about 1024.2 g/mol).

Which is heavier, Melanotan II or Cartalax?

Melanotan II has a molecular weight of about 1024.2 g/mol and Cartalax about 333.29 g/mol (PubChem), so Melanotan II is heavier by 690.9 g/mol, a ratio of 3.07. This means 1 mg of Melanotan II contains 976.4 nmol versus 3,000.4 nmol for Cartalax.

How many mg of Cartalax are equimolar to 1 mg of Melanotan II?

1 mg of Melanotan II (MW 1024.2) is 976.4 nmol. The same number of moles of Cartalax (MW 333.29) weighs 0.3254 mg. Equimolar comparisons matter when testing two compounds side by side in the same assay.

Compare the molecular formulas of Melanotan II and Cartalax

PubChem lists Melanotan II as C50H69N15O9 (1024.2 g/mol) and Cartalax as C12H19N3O8 (333.29 g/mol). Melanotan II is a cyclic peptide; Cartalax is a peptide. These formulas refer to the parent compounds without salt counter-ions.

What is the difference between Melanotan II and Matrixyl?

Melanotan II is a cyclic heptapeptide alpha-MSH analogue used as a non-selective melanocortin receptor agonist in receptor-pharmacology research (cyclic peptide, MW about 1024.2 g/mol).

Which is heavier, Melanotan II or Matrixyl?

Melanotan II has a molecular weight of about 1024.2 g/mol and Matrixyl about 802.1 g/mol (PubChem), so Melanotan II is heavier by 222.1 g/mol, a ratio of 1.28. This means 1 mg of Melanotan II contains 976.4 nmol versus 1,246.7 nmol for Matrixyl.

How many mg of Matrixyl are equimolar to 1 mg of Melanotan II?

1 mg of Melanotan II (MW 1024.2) is 976.4 nmol. The same number of moles of Matrixyl (MW 802.1) weighs 0.7831 mg. Equimolar comparisons matter when testing two compounds side by side in the same assay.

Compare the molecular formulas of Melanotan II and Matrixyl

PubChem lists Melanotan II as C50H69N15O9 (1024.2 g/mol) and Matrixyl as C39H75N7O10 (802.1 g/mol). Melanotan II is a cyclic peptide; Matrixyl is a lipopeptide. These formulas refer to the parent compounds without salt counter-ions.

What is the difference between Melanotan II and SNAP-8?

Melanotan II is a cyclic heptapeptide alpha-MSH analogue used as a non-selective melanocortin receptor agonist in receptor-pharmacology research (cyclic peptide, MW about 1024.2 g/mol).

Which is heavier, Melanotan II or SNAP-8?

Melanotan II has a molecular weight of about 1024.2 g/mol and SNAP-8 about 1075.2 g/mol (PubChem), so SNAP-8 is heavier by 51 g/mol, a ratio of 1.05. This means 1 mg of Melanotan II contains 976.4 nmol versus 930.1 nmol for SNAP-8.

How many mg of SNAP-8 are equimolar to 1 mg of Melanotan II?

1 mg of Melanotan II (MW 1024.2) is 976.4 nmol. The same number of moles of SNAP-8 (MW 1075.2) weighs 1.05 mg. Equimolar comparisons matter when testing two compounds side by side in the same assay.

Compare the molecular formulas of Melanotan II and SNAP-8

PubChem lists Melanotan II as C50H69N15O9 (1024.2 g/mol) and SNAP-8 as C41H70N16O16S (1075.2 g/mol). Melanotan II is a cyclic peptide; SNAP-8 is a peptide. These formulas refer to the parent compounds without salt counter-ions.

What is the difference between Melanotan II and Pal-GHK?

Melanotan II is a cyclic heptapeptide alpha-MSH analogue used as a non-selective melanocortin receptor agonist in receptor-pharmacology research (cyclic peptide, MW about 1024.2 g/mol).

Which is heavier, Melanotan II or Pal-GHK?

Melanotan II has a molecular weight of about 1024.2 g/mol and Pal-GHK about 578.8 g/mol (PubChem), so Melanotan II is heavier by 445.4 g/mol, a ratio of 1.77. This means 1 mg of Melanotan II contains 976.4 nmol versus 1,727.7 nmol for Pal-GHK.

How many mg of Pal-GHK are equimolar to 1 mg of Melanotan II?

1 mg of Melanotan II (MW 1024.2) is 976.4 nmol. The same number of moles of Pal-GHK (MW 578.8) weighs 0.5651 mg. Equimolar comparisons matter when testing two compounds side by side in the same assay.

Compare the molecular formulas of Melanotan II and Pal-GHK

PubChem lists Melanotan II as C50H69N15O9 (1024.2 g/mol) and Pal-GHK as C30H54N6O5 (578.8 g/mol). Melanotan II is a cyclic peptide; Pal-GHK is a lipopeptide. These formulas refer to the parent compounds without salt counter-ions.

What is the difference between Melanotan II and P21?

Melanotan II is a cyclic heptapeptide alpha-MSH analogue used as a non-selective melanocortin receptor agonist in receptor-pharmacology research (cyclic peptide, MW about 1024.2 g/mol).

Which is heavier, Melanotan II or P21?

Melanotan II has a molecular weight of about 1024.2 g/mol and P21 about 578.7 g/mol (PubChem), so Melanotan II is heavier by 445.5 g/mol, a ratio of 1.77. This means 1 mg of Melanotan II contains 976.4 nmol versus 1,728 nmol for P21.

How many mg of P21 are equimolar to 1 mg of Melanotan II?

1 mg of Melanotan II (MW 1024.2) is 976.4 nmol. The same number of moles of P21 (MW 578.7) weighs 0.565 mg. Equimolar comparisons matter when testing two compounds side by side in the same assay.

Compare the molecular formulas of Melanotan II and P21

PubChem lists Melanotan II as C50H69N15O9 (1024.2 g/mol) and P21 as C27H42N6O8 (578.7 g/mol). Melanotan II is a cyclic peptide; P21 is a peptidomimetic. These formulas refer to the parent compounds without salt counter-ions.

What is the difference between Melanotan II and TB-500?

Melanotan II is a cyclic heptapeptide alpha-MSH analogue used as a non-selective melanocortin receptor agonist in receptor-pharmacology research (cyclic peptide, MW about 1024.2 g/mol).

Which is heavier, Melanotan II or TB-500?

Melanotan II has a molecular weight of about 1024.2 g/mol and TB-500 about 889 g/mol (PubChem), so Melanotan II is heavier by 135.2 g/mol, a ratio of 1.15. This means 1 mg of Melanotan II contains 976.4 nmol versus 1,124.9 nmol for TB-500.

How many mg of TB-500 are equimolar to 1 mg of Melanotan II?

1 mg of Melanotan II (MW 1024.2) is 976.4 nmol. The same number of moles of TB-500 (MW 889) weighs 0.868 mg. Equimolar comparisons matter when testing two compounds side by side in the same assay.

Compare the molecular formulas of Melanotan II and TB-500

PubChem lists Melanotan II as C50H69N15O9 (1024.2 g/mol) and TB-500 as C38H68N10O14 (889 g/mol). Melanotan II is a cyclic peptide; TB-500 is a peptide. These formulas refer to the parent compounds without salt counter-ions.

What is the difference between Melanotan II and IGF-1 LR3?

Melanotan II is a cyclic heptapeptide alpha-MSH analogue used as a non-selective melanocortin receptor agonist in receptor-pharmacology research (cyclic peptide, MW about 1024.2 g/mol).

Which is heavier, Melanotan II or IGF-1 LR3?

Melanotan II has a molecular weight of about 1024.2 g/mol and IGF-1 LR3 about 9111 g/mol (PubChem), so IGF-1 LR3 is heavier by 8,086.8 g/mol, a ratio of 8.9. This means 1 mg of Melanotan II contains 976.4 nmol versus 109.8 nmol for IGF-1 LR3.

How many mg of IGF-1 LR3 are equimolar to 1 mg of Melanotan II?

1 mg of Melanotan II (MW 1024.2) is 976.4 nmol. The same number of moles of IGF-1 LR3 (MW 9111) weighs 8.896 mg. Equimolar comparisons matter when testing two compounds side by side in the same assay.

A 5 mg vial of Melanotan I equals how many mg of Melanotan II in moles?

5 mg of Melanotan I (MW 1646.8) is 3.036 µmol. The same amount of Melanotan II (MW 1024.2) would weigh 3.11 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan I equals how many mg of Melanotan II in moles?

10 mg of Melanotan I (MW 1646.8) is 6.072 µmol. The same amount of Melanotan II (MW 1024.2) would weigh 6.219 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of AOD 9604 in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of AOD 9604 (MW 1815.1) would weigh 17.722 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of ARA-290 in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of ARA-290 (MW 1257.3) would weigh 12.276 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of BPC-157 in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of BPC-157 (MW 1419.5) would weigh 13.86 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of CJC-1295 in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of CJC-1295 (MW 3647.2) would weigh 35.61 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of Cartalax in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of Cartalax (MW 333.29) would weigh 3.254 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of DSIP in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of DSIP (MW 848.8) would weigh 8.287 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of Dihexa in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of Dihexa (MW 504.7) would weigh 4.928 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of Epitalon in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of Epitalon (MW 390.35) would weigh 3.811 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of FOXO4-DRI in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of FOXO4-DRI (MW 5358) would weigh 52.314 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of GHK-Cu in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of GHK-Cu (MW 402.92) would weigh 3.934 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of GHRP-2 in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of GHRP-2 (MW 818) would weigh 7.987 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of GHRP-6 in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of GHRP-6 (MW 873) would weigh 8.524 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of Hexarelin in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of Hexarelin (MW 887) would weigh 8.66 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of IGF-1 LR3 in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of IGF-1 LR3 (MW 9111) would weigh 88.957 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of Ipamorelin in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of Ipamorelin (MW 711.9) would weigh 6.951 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of KPV in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of KPV (MW 342.43) would weigh 3.343 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of LL-37 in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of LL-37 (MW 4493) would weigh 43.868 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of MOTS-c in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of MOTS-c (MW 2174.6) would weigh 21.232 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of Matrixyl in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of Matrixyl (MW 802.1) would weigh 7.831 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of Melanotan I in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of Melanotan I (MW 1646.8) would weigh 16.079 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of NAD+ in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of NAD+ (MW 663.4) would weigh 6.477 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of Oxytocin in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of Oxytocin (MW 1007.2) would weigh 9.834 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of P21 in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of P21 (MW 578.7) would weigh 5.65 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of PT-141 in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of PT-141 (MW 1025.2) would weigh 10.01 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of Pal-GHK in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of Pal-GHK (MW 578.8) would weigh 5.651 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of Pinealon in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of Pinealon (MW 418.4) would weigh 4.085 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of SLU-PP-332 in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of SLU-PP-332 (MW 290.3) would weigh 2.834 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of SNAP-8 in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of SNAP-8 (MW 1075.2) would weigh 10.498 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of SS-31 in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of SS-31 (MW 639.8) would weigh 6.247 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of Selank in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of Selank (MW 751.9) would weigh 7.341 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of Semaglutide in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of Semaglutide (MW 4114) would weigh 40.168 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of Semax in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of Semax (MW 813.9) would weigh 7.947 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of Sermorelin in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of Sermorelin (MW 3357.9) would weigh 32.786 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of TB-500 in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of TB-500 (MW 889) would weigh 8.68 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of Tesamorelin in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of Tesamorelin (MW 5136) would weigh 50.146 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of Tirzepatide in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of Tirzepatide (MW 4813) would weigh 46.993 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of Triptorelin in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of Triptorelin (MW 1311.4) would weigh 12.804 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of Vesugen in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of Vesugen (MW 390.39) would weigh 3.812 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 10 mg vial of Melanotan II equals how many mg of Vilon in moles?

10 mg of Melanotan II (MW 1024.2) is 9.764 µmol. The same amount of Vilon (MW 275.3) would weigh 2.688 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of AOD 9604 in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of AOD 9604 (MW 1815.1) would weigh 8.861 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of ARA-290 in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of ARA-290 (MW 1257.3) would weigh 6.138 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of BPC-157 in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of BPC-157 (MW 1419.5) would weigh 6.93 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of CJC-1295 in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of CJC-1295 (MW 3647.2) would weigh 17.805 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of Cartalax in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of Cartalax (MW 333.29) would weigh 1.627 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of DSIP in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of DSIP (MW 848.8) would weigh 4.144 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of Dihexa in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of Dihexa (MW 504.7) would weigh 2.464 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of Epitalon in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of Epitalon (MW 390.35) would weigh 1.906 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of FOXO4-DRI in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of FOXO4-DRI (MW 5358) would weigh 26.157 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of GHK-Cu in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of GHK-Cu (MW 402.92) would weigh 1.967 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of GHRP-2 in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of GHRP-2 (MW 818) would weigh 3.993 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of GHRP-6 in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of GHRP-6 (MW 873) would weigh 4.262 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of Hexarelin in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of Hexarelin (MW 887) would weigh 4.33 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of IGF-1 LR3 in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of IGF-1 LR3 (MW 9111) would weigh 44.479 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of Ipamorelin in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of Ipamorelin (MW 711.9) would weigh 3.475 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of KPV in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of KPV (MW 342.43) would weigh 1.672 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of LL-37 in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of LL-37 (MW 4493) would weigh 21.934 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of MOTS-c in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of MOTS-c (MW 2174.6) would weigh 10.616 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of Matrixyl in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of Matrixyl (MW 802.1) would weigh 3.916 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of Melanotan I in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of Melanotan I (MW 1646.8) would weigh 8.039 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of NAD+ in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of NAD+ (MW 663.4) would weigh 3.239 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of Oxytocin in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of Oxytocin (MW 1007.2) would weigh 4.917 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of P21 in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of P21 (MW 578.7) would weigh 2.825 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of PT-141 in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of PT-141 (MW 1025.2) would weigh 5.005 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of Pal-GHK in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of Pal-GHK (MW 578.8) would weigh 2.826 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of Pinealon in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of Pinealon (MW 418.4) would weigh 2.043 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of SLU-PP-332 in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of SLU-PP-332 (MW 290.3) would weigh 1.417 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of SNAP-8 in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of SNAP-8 (MW 1075.2) would weigh 5.249 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of SS-31 in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of SS-31 (MW 639.8) would weigh 3.123 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of Selank in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of Selank (MW 751.9) would weigh 3.671 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of Semaglutide in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of Semaglutide (MW 4114) would weigh 20.084 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of Semax in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of Semax (MW 813.9) would weigh 3.973 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of Sermorelin in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of Sermorelin (MW 3357.9) would weigh 16.393 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of TB-500 in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of TB-500 (MW 889) would weigh 4.34 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of Tesamorelin in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of Tesamorelin (MW 5136) would weigh 25.073 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of Tirzepatide in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of Tirzepatide (MW 4813) would weigh 23.496 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of Triptorelin in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of Triptorelin (MW 1311.4) would weigh 6.402 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of Vesugen in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of Vesugen (MW 390.39) would weigh 1.906 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

A 5 mg vial of Melanotan II equals how many mg of Vilon in moles?

5 mg of Melanotan II (MW 1024.2) is 4.882 µmol. The same amount of Vilon (MW 275.3) would weigh 1.344 mg. This equimolar conversion lets two compounds be compared at matched molar amounts in the same experiment.

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Plain

Sable Peptides. (2026). What is the difference between Melanotan I and Melanotan II?. UK Research Peptide Reference. Retrieved 11 October 2026, from https://www.sablepeptides.co.uk/questions/compare/melanotan-i-vs-melanotan-ii/#sqa-040064

APA

Sable Peptides. (2026, October 11). *What is the difference between Melanotan I and Melanotan II?*. UK Research Peptide Reference. https://www.sablepeptides.co.uk/questions/compare/melanotan-i-vs-melanotan-ii/#sqa-040064

BibTeX

@misc{sable_#sqa-040064_2026,
  author = {{Sable Peptides}},
  title = {{What is the difference between Melanotan I and Melanotan II?}},
  year = {2026},
  howpublished = {\url{https://www.sablepeptides.co.uk/questions/compare/melanotan-i-vs-melanotan-ii/#sqa-040064}},
  note = {Accessed 11 October 2026. CC BY 4.0}
}

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Date modified: 2026-10-10